PHASE 1 — Comprehensive Analysis & Study Guide
Derived from Section B & C long-answer patterns across 15 papers
1.1 Topic Frequency & Weightage Breakdown
How this was built: Every Section B/C question (3–5 marks each) across the 2018–2025 papers was tallied by topic. Tier 1 topics appeared in 10+ of 15 papers — treat these as non-negotiable.
Topic
Priority
Freq. (papers)
Typical Question Form
Electric dipole — potential & field (short/physical dipole, coordinate-free form)
TIER 1
~12/15
Derive V and E of a dipole; show coordinate-free form
Electric field of a charged disc / ring at axial point z
TIER 1
~10/15
Find E at distance z above disc of radius R, check R→∞ and z≫R limits
Bound charge in cavity of polarized dielectric → Clausius-Mossotti
TIER 1
~9/15
Show E(center) = P/3ε₀; derive Clausius-Mossotti equation
Mutual inductance — Neumann formula & Reciprocity theorem
Explain the three terms; derive χ for diamagnetic material (Langevin)
Magnetic dipole: torque & energy in uniform B
TIER 2
~4/15
Derive N=m×B, U=−m·B; max/min energy conditions
Work-energy theorem of electrodynamics
TIER 3
~3/15
State and prove dW/dt = ∫(E·J)dτ
Self-inductance of coaxial cable / solenoid
TIER 3
~4/15
Find energy stored, then self-inductance L from U=½LI²
Nuclear reactor working principle
TIER 3
~2/15
Labeled diagram + working principle description
1.2 Most Repeated & High-Probability Predicted Questions
A. Verbatim / Near-Verbatim Repeats (appeared 3+ times)
#
Question (as it recurs)
Marks
1
Find the electric field a distance z above the center of a flat circular disc of radius R carrying uniform surface charge σ. Check R→∞ and z≫R.
5
2
A spherical cavity of radius R is made inside a uniformly polarized dielectric medium. Find E at the center due to bound charges; hence obtain the Clausius–Mossotti equation.
5
3
Define mutual inductance. Derive the Neumann formula and state the reciprocity theorem.
3–5
4
State and prove Poynting's theorem; show that S satisfies ∇·S = −∂/∂t(U_em+U_mech).
5
5
Explain the Raman Effect with a schematic diagram and give its quantum-mechanical explanation with an energy-level diagram.
5
6
How did Maxwell correct Ampère's law? Derive Maxwell's equations in a medium / derive the EM wave equation in vacuum.
3–5
7
Find the magnetic field on the axis of a tightly wound solenoid (n turns/length, current I) in terms of θ₁ and θ₂; deduce the field for an infinite solenoid.
5
8
Find the approximate potential & electric field of a physical dipole at points far away; write the coordinate-free form of E_dip.
3–5
9
Derive the half-life expression T½ = (ln2)Δt / ln(R₀/R); or solve a numerical half-life problem (e.g., radon 3.8-day half-life).
3–5
10
Derive the expression for threshold energy: E_th = Q(1 + Ma/Mx).
5
11
Using Ampère's law, find B inside and outside a long wire carrying volume current density J = kr.
3–5
12
Show that hysteresis loss per cycle equals the area enclosed by the B–H hysteresis loop.
3–5
13
Calculate the binding energy per nucleon of tritium / carbon-12 given atomic masses.
3–5
14
Show that the electric field at the center of a cavity in a uniformly polarized medium is P/3ε₀.
5
15
Show that the energy stored in a magnetic field B is U = (1/2μ₀)∫B²dτ.
3–5
B. Predicted Questions for Upcoming Exams (based on cyclical pattern)
Prediction logic: Papers alternate a fixed pool of ~28 long-answer "core" questions between OR-choices. Any topic tier-1/tier-2 above that has not appeared in the last 2 papers is due to reappear.
Derive the expression for the electric field of an infinite/finite line charge (distance z above one end) — due.
Derive work done to assemble n point charges → energy of continuous charge distribution W = (ε₀/2)∫E²dτ — due.
Derive the vector potential of an infinite solenoid — due (seen only once recently).
Explain domain theory / hysteresis with B–H curve sketch — recurring every 2–3 sessions.
Derive Q-value expression for a nuclear reaction a+X→Y+b in terms of kinetic energies/masses — high probability.
Derive self-inductance & energy stored in a coaxial cable of radii a, b — recurring every 2–3 sessions.
1.3 High-Yield Notes — Formula & Concept Sheet
Electrostatics
Coulomb / Gauss
E = (1/4πε₀)Σqᵢr̂ᵢ/rᵢ² | ∮E·da = Q_enc/ε₀ | V(r) = (1/4πε₀)∫ρ/r dτ | E = −∇V
Binding Energy = [Zm_p+(A−Z)m_n−M_nucleus]c² (use 1u=931.5 MeV) | Q = (Σm_reactants−Σm_products)c² | Threshold energy: E_th = Q(1+M_a/M_X) (Q<0, target X at rest)
Raman Effect
Stokes lines: scattered photon loses energy to molecule (ν₀−ν_vib), longer λ, more intense | Anti-Stokes: gains energy (ν₀+ν_vib), shorter λ, less intense (fewer molecules in excited vibrational state at room T)
Superconductivity
Meissner effect: B expelled from interior (perfect diamagnet, χ=−1) below Tc | B_c(T) = B_c0[1−(T/Tc)²]
1.4 Common Pitfalls — Where Marks Are Lost
Mistake
Why marks are lost
Exact Fix
Confusing E-field direction/sign for disc/dipole problems
Sign errors in θ dependence or forgetting the ẑ vs r̂ direction cost 1–2 marks even with correct magnitude
Always state the coordinate system first (cylindrical for disc, spherical for dipole) and box the final vector, not just magnitude
Skipping boundary/limit checks (R→∞, z≫R)
Examiners explicitly award 1 mark for verifying the two limiting cases — students who compute E but skip limits lose these
Always finish disc/rod problems by explicitly plugging in the two limits and stating the physical interpretation ("reduces to infinite sheet formula")
Writing Neumann formula without stating Coulomb gauge / reciprocity proof steps
Half-derivations (just quoting the formula) get partial credit only
Always start from Φ₂=∫B₁·da₂, substitute A₁, then swap integration order to prove M₁₂=M₂₁
Mixing up ∇×H=J_f+∂D/∂t vs ∇×B=μ₀J+μ₀ε₀∂E/∂t
Using vacuum form when question says "in a medium" (or vice versa) — instant deduction
Underline the keyword "matter/medium" vs "vacuum" in the question before writing equations
Forgetting the negative sign / continuity form in Poynting theorem
Poynting theorem proofs are marked step-wise; missing the −∂U/∂t sign breaks the "law of conservation" interpretation
Explicitly write "energy leaving = decrease of stored energy", so the minus sign is justified in words, not just algebra
Not converting u (atomic mass unit) to MeV correctly in binding-energy numericals
Using 1u = 1.66×10⁻²⁷ kg then forgetting to convert to MeV via c², or misusing 931.5 MeV/u factor
Memorize 1u = 931.5 MeV/c² and always compute Δm in u first, then multiply directly by 931.5 to get MeV
Sign error in Q-value / threshold energy formula
Students forget Q is negative for endothermic reactions, making E_th come out negative
State explicitly "Q is negative for endothermic reaction" before substituting into E_th = Q(1+M_a/M_X)
Applying Gauss/Ampère's law without justifying symmetry
0.5–1 mark reserved just for "by symmetry, B is tangential and constant along the loop"
Always write one line justifying the choice of Gaussian surface / Amperian loop symmetry before integrating
Confusing Stokes vs anti-Stokes intensity/wavelength in Raman effect
A very common flip — students say Stokes has shorter λ or lower intensity
MCQs use one flipped sign to test rote memorization
Learn the identities from first principles once: ∇×(fA)=f∇×A−A×∇f and ∇×(∇×A)=∇(∇·A)−∇²A — derive them once, don't just memorize
Not showing units / dimensional check in fill-in-the-blank numericals
Even correct final numbers lose marks without units (A/m, C/m², J, etc.)
Always append SI unit to every fill-in-the-blank final answer
PHASE 2 — Master MCQ Practice Bank & Answer Key
40 questions compiled & adapted from Section "A" across all papers — with full working
Each card shows the topic tag, four options, and a fully worked answer. Cover the answer box with your hand and self-test first (see Active Recall plan in the strategic roadmap).
Q1Vector Calculus
The divergence of the vector function F⃗ = xe⁻ˣî + yĵ − xzk̂ is:
Point charge Q₁ lies inside sphere S₁ (radius R₁); point charge Q₂ lies outside S₁ but inside concentric sphere S₂ (radius R₂). If φ₁, φ₂ are fluxes through S₁, S₂ respectively:
A. φ₁/φ₂ = Q₁/Q₂
B. φ₁/φ₂ = Q₁/(Q₁+Q₂)
C. φ₁/φ₂ = (Q₁+Q₂)/Q₂
D. φ₁/φ₂ = Q₁R₁²/Q₂R₂²
Answer: B. By Gauss's law, φ₁ = Q₁/ε₀ (only Q₁ enclosed), φ₂ = (Q₁+Q₂)/ε₀ (both enclosed). Ratio = Q₁/(Q₁+Q₂).
Q3Electrostatics — Shells
Let V and E be the potential and field inside a spherical shell carrying uniformly distributed total charge q. Which is correct everywhere inside the shell?
A. V=0, E≠0
B. V≠0, E≠0
C. V=0, E=0
D. V≠0, E=0
Answer: D. Inside a uniform spherical shell E=0 (Gauss's law, no enclosed charge), but V is constant and equal to the (non-zero) surface potential kq/R, not zero.
Q4Dielectrics
The electric potential V (in volts) as a function of distance x (in metres) is V = 10x² + 10x − 100. The electric field at x = 2 m is:
A. 20 V/m
B. −40 V/m
C. −60 V/m
D. −50 V/m
Answer: D. E = −dV/dx = −(20x+10). At x=2: E = −(40+10) = −50 V/m.
Q5Magnetism — Materials
Which one of the following materials is an example of a paramagnetic substance?
A. Copper
B. Gold
C. Cobalt
D. Platinum
Answer: D. Platinum is paramagnetic. Copper & gold are diamagnetic; cobalt is ferromagnetic.
Q6Nuclear Physics
Which process releases energy in the Sun?
A. Fission
B. Haber's process
C. Fusion
D. Radioactivity
Answer: C. Fusion — light nuclei (H isotopes) combine to form He, releasing energy (mass defect × c²).
Q7Nuclear Decay
In the alpha decay ²³⁸₉₂U → ᴬ_Z X + α, the values of Z and A for the daughter nucleus are:
A. Z=92, A=238
B. Z=90, A=234
C. Z=93, A=238
D. Z=88, A=236
Answer: B. α = ⁴₂He removes 2 protons & 2 neutrons: Z = 92−2 = 90, A = 238−4 = 234.
Q8Inductance
The self-inductance per unit length of a long solenoid of radius R and n turns per unit length carrying current I is:
A. μ₀πnR²
B. μ₀πnIR²
C. (3/4)μ₀πn²R³
D. μ₀πn²R²
Answer: D. Flux linkage per unit length = n·(nI·μ₀·πR²)= μ₀n²IπR², so L per unit length = μ₀πn²R² (independent of I).
Q9Maxwell's Equations
Which equation is a direct consequence of ∇×H = J_f + ∂D/∂t?
A. ∇(J_f·∂D/∂t) = 0
B. ∇×(J_f+∂D/∂t) = 0
C. J_f + ∂D/∂t = 0
D. ∇·(J_f+∂D/∂t) = 0
Answer: D. Taking the divergence of both sides: ∇·(∇×H)=0 identically, so ∇·(J_f+∂D/∂t)=0 — this is exactly the continuity/consistency condition Maxwell needed to fix Ampère's law.
Q10Vector Calculus
The divergence of the position vector r⃗ = xî+yĵ+zk̂ at the point (3, 2, −4) is:
A. 0
B. 3
C. 9
D. −4
Answer: B. ∇·r⃗ = ∂x/∂x+∂y/∂y+∂z/∂z = 1+1+1 = 3, a constant independent of position.
Q11Electrostatics — Sphere
The potential difference between the center and the surface of a solid sphere (radius R, uniform volume charge density ρ) is:
The energy per unit time per unit area transported by electromagnetic fields is called the:
A. Polarization vector
B. Poynting vector
C. Electric displacement vector
D. Magnetization vector
Answer: B. Poynting vector, S = (1/μ₀)(E×B), with SI units W/m².
Q13Electrostatics
The work done to move a charge from one point to another on an equipotential surface is:
A. Constant
B. Infinity
C. Zero
D. Negative
Answer: C. Zero — W = qΔV, and ΔV = 0 on an equipotential surface.
Q14Ferromagnetism
The area of the B–H hysteresis curve is an indication of the:
A. Energy dissipated per cycle
B. Retentivity of the material
C. Permeability of the material
D. Susceptibility of the material
Answer: A. The loop area equals ∮H·dB, the energy lost as heat per magnetization cycle.
Q15Charged Particle Motion
Cyclotron frequency of a charged particle circling in a magnetic field is independent of:
A. Charge of the particle
B. Mass of the particle
C. Speed of the particle
D. Magnetic field strength
Answer: C. Speed. f = qB/2πm — depends only on q, B, m, not on v (radius adjusts to keep f fixed).
Q16Ferromagnetism
The magnetization left on a ferromagnetic material after removal of the magnetizing field (post-saturation) is called:
A. Coercivity
B. Retentivity
C. Permeability
D. Susceptibility
Answer: B. Retentivity (remanence) — the coercivity is instead the reverse field needed to demagnetize.
Q17Superconductivity
A superconductor (below Tc) is characterized by:
A. R=0, B=0, χ_magnetic=0
B. R=0, B=∞, χ_magnetic=0
C. R=0, B=0, χ_magnetic<0
D. R=0, B=0, χ_magnetic>0
Answer: C. Meissner effect: B expelled (B=0 inside), and the material behaves as a perfect diamagnet, χ = −1 < 0.
Q18Superconductivity — Numerical
Tin has critical temperature Tc = 3.7 K with critical field Bc0 = 0.0306 T at 0 K. The critical field at T = 2 K is:
A. 0.0102 T
B. 0.0166 T
C. 0.0217 T
D. 0.0306 T
Answer: C ≈ 0.0217 T. Bc(T)=Bc0[1−(T/Tc)²] = 0.0306×[1−(2/3.7)²] = 0.0306×(1−0.2921) = 0.0306×0.7079 ≈ 0.02166 T.
Q19Magnetic Field — Wires
Two long straight parallel wires, separated by distance d, carry equal current I in opposite directions. The magnitude of B at the midpoint between them is:
A. μ₀I/(2πd)
B. μ₀I/(πd)
C. 2μ₀I/(πd)
D. Zero
Answer: C. Each wire gives B=μ₀I/(2π(d/2))=μ₀I/(πd) at the midpoint; since currents are opposite, fields add: total = 2μ₀I/(πd).
Q20Dielectrics — Numerical
The dielectric constant of salt is 5.9. The ratio of bound charge to free charge density magnitude in a unit volume is:
Answer: C. Ferromagnetic materials organize into domains — regions of aligned atomic magnetic moments.
Q22Polarization Units
The SI unit of polarization (P) is:
A. C/m²
B. C·m
C. C/m³
D. A/m
Answer: A. C/m² — same units as surface charge density since σ_b = P·n̂.
Q23Molecular Spectroscopy
The vibrational spectra of a molecule fall in the far infra-red region, while the rotational spectra fall in the:
A. Ultraviolet region
B. Visible region
C. Microwave region
D. X-ray region
Answer: C. Microwave region — rotational energy spacings are smaller than vibrational, so transitions occur at longer wavelengths (microwave).
Q24Gauss's Law — Geometry
A cube is inscribed in a sphere of radius r, with a positive point charge Q at the common center. The ratio of electric flux through the sphere (Φ_sphere) to that through the cube surface (Φ_cube) is:
A. 1
B. 4/3
C. 2√3/3
D. √3/2
Answer: A. 1. By Gauss's law, total flux through any closed surface enclosing charge Q is Q/ε₀ regardless of shape — sphere and cube enclose the same Q, so their total fluxes are equal.
Q25Magnetic Materials
The superconducting state is perfectly ______ in nature.
A coil has inductance 10 H and resistance 20 Ω. If a 200 V emf is applied, the energy stored in the magnetic field once current builds to its maximum value (I_max = V/R) is:
A. 200 J
B. 250 J
C. 500 J
D. 1000 J
Answer: C. 500 J. I_max = V/R = 200/20 = 10 A. U = ½LI² = ½×10×(10)² = 500 J.
Q30Radioactive Decay — Numerical
The half-life of a radioactive substance is 693 years. Its disintegration constant λ is approximately:
A. 1×10⁻³ yr⁻¹
B. 6.93×10⁻³ yr⁻¹
C. 1×10⁻² yr⁻¹
D. 6.93×10⁻⁴ yr⁻¹
Answer: A ≈ 1×10⁻³ yr⁻¹. λ = ln2/T½ = 0.693/693 = 1.0×10⁻³ per year.
Q31Nuclear Decay
If a radioactive nuclide ᴬ_Z X decays by emitting a gamma ray only, what happens to A and Z?
A. Z changes, A unchanged
B. A and Z both unchanged
C. A changes, Z unchanged
D. Both A and Z decrease by 1
Answer: B. Gamma emission is a de-excitation of the nucleus (photon only) — no change in proton or nucleon number.
Q32Vector Identities
Which of the following vector identities is NOT correct? (A,B are vector fields, f is scalar)
A. ∇×(fA) = f∇×A − A×∇f
B. ∇×(∇×A) = ∇(∇·A) − ∇²A
C. ∇×(A×B) = B×(∇×A) − A×(∇×B)
D. ∇·(A×B) = B·(∇×A) − A·(∇×B)
Answer: C is NOT correct. The true identity is ∇×(A×B) = A(∇·B) − B(∇·A) + (B·∇)A − (A·∇)B — it involves divergence and directional-derivative terms, not curl cross products as stated in C. A, B, D are standard correct vector identities.
Q33Charged Particle Motion
A charged particle is released from rest in a region with constant, parallel E and B fields. The path of the particle is a:
A. Circle
B. Helix
C. Cycloid
D. Straight line
Answer: D. Straight line. At t=0, v=0 so the magnetic force qv×B=0; the particle accelerates only along E (which is parallel to B), so it continues moving along that single line — v stays parallel to B for all time, keeping qv×B=0 throughout.
Q34Ampère's Law — Geometry
An Amperian loop is valid (line integral calculable) only if, along the loop:
A. B is tangential and varies uniformly along the loop
B. B is tangential and constant at every point on the loop
C. B is perpendicular and varies uniformly along the loop
D. B is perpendicular and constant at every point on the loop
Answer: B. Symmetry must make B tangential (so B·dl=B dl) and of constant magnitude along the chosen loop so ∮B·dl = B×(loop length) can be solved for B.
Q35Diamagnetism — Concept
A material has atomic/molecular dipoles that are randomly oriented with zero net moment in the absence of a field, arising purely from electron spin, and the atoms/molecules contain an odd number of electrons. This material is called:
A. Diamagnetic
B. Ferromagnetic
C. Paramagnetic
D. Anti-ferromagnetic
Answer: C. Paramagnetic. Odd number of electrons → net unpaired spin moment per atom (though randomly oriented without field) — hallmark of paramagnetism, unlike diamagnetism which needs no permanent atomic moment at all.
Q36Raman Spectroscopy
In Raman spectra:
A. Stokes lines have shorter wavelength and are less intense than anti-Stokes
B. Stokes lines have longer wavelength and are more intense than anti-Stokes
C. Stokes lines have longer wavelength and are less intense than anti-Stokes
D. Stokes lines have shorter wavelength and are more intense than anti-Stokes
Answer: B. Stokes photons lose energy to the molecule (ν₀−ν_vib) → longer λ; since most molecules start in the ground vibrational state, Stokes transitions are more probable/intense than anti-Stokes.
Q37Curl of Electric Field
In the region of free space with no charge or current, the curl of curl of Faraday's induced electric field E is:
A. ε₀μ₀ ∂²E/∂t²
B. μ₀ ∂²E/∂t²
C. ε₀ ∂²E/∂t²
D. (1/ε₀μ₀) ∂²E/∂t²
Answer: A. ∇×(∇×E) = ∇×(−∂B/∂t) = −∂/∂t(∇×B) = −∂/∂t(μ₀ε₀∂E/∂t) → using ∇×(∇×E)=∇(∇·E)−∇²E=−∇²E (since ∇·E=0), we get −∇²E = −μ₀ε₀∂²E/∂t² i.e. ∇×(∇×E) = μ₀ε₀ ∂²E/∂t².
Q38Solenoid Field — Geometry
For a solenoid on-axis field, the finite-solenoid result B=(μ₀nI/2)(cosθ₂−cosθ₁) reduces to B=μ₀nI for an infinite solenoid because:
A. θ₁→0°, θ₂→180°
B. θ₁→180°, θ₂→0°
C. θ₁=θ₂=90°
D. θ₁→90°, θ₂→90°
Answer: A. As the solenoid becomes infinite, the near end subtends θ₁→0° (cosθ₁→1) and far end θ₂→180° (cosθ₂→−1): B=(μ₀nI/2)(−1−1)=−μ₀nI (sign depends on convention) → magnitude μ₀nI.
Q39Magnetic Dipole Energy
A magnetic dipole possesses maximum potential energy inside a uniform magnetic field when:
A. Magnetic moment & field are antiparallel
B. Magnetic moment & field are parallel
C. The magnetic moment is zero
D. The magnetic field is zero
Answer: A. U = −m·B = −mB cosθ. Maximum U occurs at θ=180° (antiparallel), giving U=+mB, the highest (least negative/most positive) value.
Q40Beta Decay — Concept
The electron emitted in β⁻ radiation originates from:
A. Inner orbits of atoms
B. Free electrons existing in the nucleus
C. The decay of a neutron in the nucleus
D. A photon escaping from the nucleus
Answer: C. β⁻ decay: n → p + e⁻ + ν̄ₑ (a neutron converts to a proton, emitting an electron and antineutrino) — electrons are not pre-existing in the nucleus.